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29x-x^2-100=0
We add all the numbers together, and all the variables
-1x^2+29x-100=0
a = -1; b = 29; c = -100;
Δ = b2-4ac
Δ = 292-4·(-1)·(-100)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-21}{2*-1}=\frac{-50}{-2} =+25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+21}{2*-1}=\frac{-8}{-2} =+4 $
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